If $AB = 5$, $BC = 5$, $AC = 10$, and points are collinear, then $B$ is

If $AB = 5$, $BC = 5$, $AC = 10$, and points are collinear, then $B$ is

the midpoint of $AC$
end-point
outside segment $AC$
a different point

Solution

$AB = BC = 5$ and $B$ is between, so midpoint.

Asked in: MH-SSC-9

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