If $A=\{2,4\}, \quad B=\{3,4,5\}$, then $(\mathrm{A} \cap \mathrm{B}) \times(\mathrm{AUB})=$
If $A=\{2,4\}, \quad B=\{3,4,5\}$, then $(\mathrm{A} \cap \mathrm{B}) \times(\mathrm{AUB})=$
- $\{(3,2),(3,4),(4,4),(5,4)\}$
- $\{(2,3),(2,4),(2,5)\}$
- $\{(4,2),(4,3),(4,4),(4,5)\}$
- $\{(4,3),(4,4),(4,5)\}$
Solution
$\mathrm{A} \cap \mathrm{B}=\{4\}$
$\mathrm{A} \cup \mathrm{B}=\{2,3,4,5\}$
Hence
$(\mathrm{A} \cap \mathrm{B}) \times(\mathrm{A} \cup \mathrm{B})$
$=\{(4,2),(4,3),(4,4),(4,5)\}$
Asked in: MHT CET 2020 (12 Oct Shift 1)
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