If $a \cdot b = 18$ and the product $(2a)(3b)$ equals $k$, find $k$.

If $a \cdot b = 18$ and the product $(2a)(3b)$ equals $k$, find $k$.
  1. $108$
  2. $54$
  3. $36$
  4. $216$

Solution

$(2a)(3b) = 6ab = 6 \times 18 = 108$.

Asked in: IMO

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