If $a, b, c$ are in continued proportion and $a = 4, c = 9$, then $b$ equals

If $a, b, c$ are in continued proportion and $a = 4, c = 9$, then $b$ equals
  1. $6$
  2. $\dfrac{13}{2}$
  3. $36$
  4. $13$

Solution

$b^{2} = ac = 36 \Rightarrow b = 6$.

Asked in: MH-SSC-9

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