If $a + b = 4$ and $ab = 3$, find $a^{3} + b^{3}$.
If $a + b = 4$ and $ab = 3$, find $a^{3} + b^{3}$.
- $28$
- $64$
- $36$
- $12$
Solution
$(a+b)^{3} = a^{3}+b^{3}+3ab(a+b) \Rightarrow 64 = a^{3}+b^{3}+36 \Rightarrow 28$.
Asked in: IMO
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