If $4 \le x \le 8$ and $2 \le y \le 7$, then what is the ratio of maximum value of $(x + y)$ to minimum…
If $4 \le x \le 8$ and $2 \le y \le 7$, then what is the ratio of maximum value of $(x + y)$ to minimum value of $(x - y)$?
6
$\dfrac{15}{2}$
$-\dfrac{15}{2}$
None of the above
Solution
Maximum value of $(x+y)$ = $8 + 7 = 15$. Minimum value of $(x-y)$ = smallest $x$ minus largest $y$ = $4 - 7 = -3$. The ratio = $\dfrac{15}{-3} = -5$. Since $-5$ is none of the listed options (a), (b) or (c), the answer is 'None of the above'.