If $2 \cos ^{2} \theta+3 \cos \theta=2$, then permissible value of $\cos \theta$ is

If $2 \cos ^{2} \theta+3 \cos \theta=2$, then permissible value of $\cos \theta$ is
  1. 0
  2. 1
  3. $\frac{1}{2}$
  4. $\frac{-1}{2}$

Solution

We have $2 \cos ^{2} \theta+3 \cos \theta=2$ $2 \cos ^{2} \theta+4 \cos \theta-\cos \theta-2=0 \Rightarrow 2 \cos \theta(\cos \theta+2)-1(\cos \theta+2)=0$ $(2 \cos \theta-1)(\cos \theta+2)=0$ $\therefore \cos \theta=\frac{1}{2},-2($ Impossible $) \Rightarrow \cos \theta=\frac{1}{2}$

Asked in: MHT CET 2020 (19 Oct Shift 2)

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