If $a>0$ discriminant of $a x^2+2 b x+c$ is -ve, then $\left|\begin{array}{ccc}a & b & a x+b \\ b & c & b…

If $a>0$ discriminant of $a x^2+2 b x+c$ is -ve, then $\left|\begin{array}{ccc}a & b & a x+b \\ b & c & b x+c \\ a x+b & b x+c & 0\end{array}\right|$ is
  1. +ve
  2. $\left(a c-b^2\right)\left(a x^2+2 b x+c\right)$
  3. -ve
  4. 0

Asked in: JEE Main 2002

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