If $s=60 t-5 t^2$ denotes the distance covered by a particle in time $t$, then the distance it covers before coming to rest is.... units.

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Aicharya · Accepted Answer

$s=60 t-5 t^2$ is the distance covered by a particle in time ‘t’. $\because$ At rest $v=0$ $ \begin{array}{rrr} \Rightarrow & \frac{d s}{d t}=0 \ & 60-10 t=0 \ \Rightarrow & t=6 \mathrm{~s} \end{array} $ $	herefore$ Distance covered in $6 \mathrm{~s}$ before coming to rest $ \begin{aligned} & =60(6)-5(6)^2 \ & =360-180=180 	ext { units. } \end{aligned} $

If $s=60 t-5 t^2$ denotes the distance covered by a particle in time $t$, then the distance it covers before…

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