If $1, \omega, \omega^2$ denote the cube roots of unity, then the value of…
If $1, \omega, \omega^2$ denote the cube roots of unity, then the value of $\left(1-\omega+\omega^2\right)^5+\left(1+\omega-\omega^2\right)^5$ is
- $32 \omega^2$
- $32 \omega$
- $-32$
- $32$
Solution
$\begin{aligned} & 1+\omega+\omega^2=0 \\ & \left(1-\omega+\omega^2\right)^5+\left(1+\omega-\omega^2\right)^5 \\ & =(-2 \omega)^5+\left(-2 \omega^2\right)^5 \\ & =-32\left(\omega^5+\omega^{10}\right)=-32\left(\omega^2+\omega\right)=32\end{aligned}$
Asked in: AP EAMCET 2022 (07 Jul Shift 2)
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