If $1, \omega, \omega^2$ denote the cube roots of unity, then the value of…

If $1, \omega, \omega^2$ denote the cube roots of unity, then the value of $\left(1-\omega+\omega^2\right)^5+\left(1+\omega-\omega^2\right)^5$ is
  1. $32 \omega^2$
  2. $32 \omega$
  3. $-32$
  4. $32$

Solution

$\begin{aligned} & 1+\omega+\omega^2=0 \\ & \left(1-\omega+\omega^2\right)^5+\left(1+\omega-\omega^2\right)^5 \\ & =(-2 \omega)^5+\left(-2 \omega^2\right)^5 \\ & =-32\left(\omega^5+\omega^{10}\right)=-32\left(\omega^2+\omega\right)=32\end{aligned}$

Asked in: AP EAMCET 2022 (07 Jul Shift 2)

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