If ∫ cos x d x sin 3 x 1 + sin 6 x 2 3 = f x 1 + sin 6 x 1 λ + c , where c is a constant of…

If cosxdxsin3x1+sin6x23=fx1+sin6x1λ+c, where c is a constant of integration, then λfπ3 is equal to
  1. -98
  2. 2
  3. 98
  4. -2

Solution

Let, sinx=t 

cosxdx=dt
I=dtt31+t623=dtt71+1t623

Put 1+1t6=r3 

dtt7=-12r2dr

I=-12r2drr2=-12r+c 

I=-12sin6x+1sin6x13+c

I=-12sin2x1+sin6x13+c

So, fx=-12cosec2x and λ=3

λfπ3=-2

Asked in: JEE Main 2020 (08 Jan Shift 1)

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