If ∫ cos x - sin x 8 - sin 2 x   d x = a sin - 1 sin x + cos x   b + c , where c is a constant of integration, then the ordered pair a , b is equal to:

Question

If &#8747; cos x - sin x 8 - sin 2 x &#160; d x = a sin - 1 sin x + cos x &#160; b + c , where c is a constant of integration, then the ordered pair a , b is equal to:

Aicharya · Accepted Answer

&#8747; cos x - sin x 8 - sin 2 x d x = &#8747; cos x - sin x 9 - sin x + cos x 2 d x Let sin x + cos x = t &#8747; d t 9 - t 2 = sin - 1 t 3 + c = sin - 1 sin x + cos x 3 + c So a = 1 , &#160; b = 3

If ∫ cos x - sin x 8 - sin 2 x   d x = a sin - 1 sin x + cos x   b + c , where c is a…

Solution

If &#8747; cos x - sin x 8 - sin 2 x &#160; d x = a sin - 1 sin x + cos x &#160; b + c , where c is a…

Solution

If ∫ cos x - sin x 8 - sin 2 x d x = a sin - 1 sin x + cos x b + c , where c is a…