If cos α + cos β = 3 2   and   sin α + sin β = 1 2   and θ is the…

If cosα+cosβ=32 and sinα+sinβ=12 and θ is the arithmetic mean of α & β, then sin2θ+cos2θ is equal to:
  1. 35
  2. 75
  3. 45
  4. 85

Solution

Given 
cos α + cos β = 32
sin α + sin β = 12
2cos(α+β2)cos(α-β2)=32 ......(i) and

2sin(α+β2)cos(α-β2)=12 ....(ii)

Dividing (ii) and (i)

tan α + β2
  tanθ =13

sin2θ+cos2θ = 2tanθ1+tan2θ+ 1-tan2θ1+tan2θ=2131+19+1-191+19

= 23+89109=1410=75

Asked in: JEE Main 2015 (11 Apr Online)

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