If c o s α + β = 3 5   , sin ⁡ ( α - β ) = 5 13 and 0 < α , β…

If cosα+β=35 ,sin(α-β)=513 and 0<α,β<π4, then tan2α is equal to:
  1. 2116
  2. 6352
  3. 3352
  4. 6316

Solution

cosα+β=35tanα+β=43

sin(α-β)=513tan(α-β)=512

Now,

tan2α=tanα+β+α-β

            =tan(α+β)+tan(α-β)1-tan(α+β)tan(α-β)

            =43+5121-43×512=6316

Asked in: JEE Main 2019 (08 Apr Shift 1)

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