If $\mathrm{SO}_{2}$ content in the atmosphere is $0.12 \mathrm{ppm}$ by volume, $\mathrm{pH}$ of rain water is (assume $100 \%$ ionisation of acid rain as monobasic acid)

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Aicharya · Accepted Answer

$0.12 \mathrm{ppm}=0.12 \mathrm{~g}$ in $10^{6} \mathrm{~mL}$
$\left[\mathrm{H}^{+}ight]=\left[\mathrm{SO}_{2}ight]$
$\therefore\left[\mathrm{H}_{2} \mathrm{SO}_{3}ight]=\frac{0.12}{64} \times 10^{-3} \mathrm{M}$
$\mathrm{pH}=5.7$

If $\mathrm{SO}_{2}$ content in the atmosphere is $0.12 \mathrm{ppm}$ by volume, $\mathrm{pH}$ of rain water…

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