If both perpendiculars on the diagonal of a quadrilateral are doubled while the diagonal stays the same, the…
If both perpendiculars on the diagonal of a quadrilateral are doubled while the diagonal stays the same, the new area is:
Same as before
Doubled
Tripled
Four times
Solution
Area $= \dfrac{1}{2} d (h_{1}+h_{2})$. Doubling both heights gives $\dfrac{1}{2} d (2h_{1}+2h_{2}) = 2 \cdot \dfrac{1}{2} d (h_{1}+h_{2})$, twice the original area.