If both diagonals of a rhombus are doubled, its area becomes:

Question

Aicharya · Accepted Answer

Area $= \dfrac{1}{2} d_{1} d_{2}$. New area $= \dfrac{1}{2}(2d_{1})(2d_{2}) = 4 \cdot \dfrac{1}{2} d_{1} d_{2}$. Hence the area becomes four times.

Solution