If $k_1>k_2$ are the two values of $\mathrm{k}$ such that the lines $y-3 k x+4=0$ and $(2 k-1) x-(8 k-1)…

If $k_1>k_2$ are the two values of $\mathrm{k}$ such that the lines $y-3 k x+4=0$ and $(2 k-1) x-(8 k-1) \mathrm{y}-6=0$ are perpendicular, then the equation of the line passing through $\left(k_1, k_2\right)$ and having the slope $\left(\frac{k_2}{k_1}\right)$ is
  1. $3 x+2 y=0$
  2. $6 x-2 y=3$
  3. $12 x-5 y=7$
  4. $6 x+y=0$

Solution

No solution. Refer to answer key.

Asked in: AP EAMCET 2017 (26 Apr Shift 2)

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