If $\vec{a}, \vec{b}$ are the two non collinear vectors. then $|\vec{b}| \vec{a}+|\vec{a}| \vec{b}$ represents
If $\vec{a}, \vec{b}$ are the two non collinear vectors. then $|\vec{b}| \vec{a}+|\vec{a}| \vec{b}$ represents
a vector parallel to an angle bisector of $\vec{a}, \vec{b}$
a vector along the difference of the vectors $\vec{a}, \vec{b}$
a vector along $\vec{a}+\vec{b}$
a vector outside the triangle having $\vec{a}, \vec{b}$ as adjacent sides
Solution
$|\overrightarrow{\mathrm{b}}| \vec{a}+|\overrightarrow{\mathrm{a}}| \vec{b}=\frac{1}{|\vec{a}||\vec{b}|}\left[\frac{\vec{a}}{|\vec{a}|}+\frac{\vec{b}}{|\vec{b}|}\right][\because \vec{a} \neq 0, \vec{b} \neq 0]$
$=k[\vec{a}+\vec{b}]$
Which is a vector parallel to an angle bisector of $\vec{a}, \vec{b}$.