If $\alpha, \beta$ are the solutions of the equation $\operatorname{Sin}^{-1} x-\operatorname{Cos}^{-1} x=\operatorname{Sin}^{-1}(3 x-2)$ and $\alpha\beta$ then $3 \alpha+4 \beta=$

Question

If $\alpha, \beta$ are the solutions of the equation $\operatorname{Sin}^{-1} x-\operatorname{Cos}^{-1} x=\operatorname{Sin}^{-1}(3 x-2)$ and $\alpha>\beta$ then $3 \alpha+4 \beta=$

Aicharya · Accepted Answer

No solution. Refer to answer key.

If $\alpha, \beta$ are the solutions of the equation $\operatorname{Sin}^{-1} x-\operatorname{Cos}^{-1}…

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