Mathematics › Quadratic Equation › N degree equation
x3-2x2+3x-4=0 αβγα+β+γ=2αβγ=4, ∑αβ=3αβ(α+β)+βγ(β+γ)+γα(γ+α)αβ(2-γ)+βγ(2-α)+γα(2-β)=2∑αβ-3αβγ=2(3)-3×4=-6
x3-2x2+3x-4=0 αβγ
α+β+γ=2
αβγ=4, ∑αβ=3
αβ(α+β)+βγ(β+γ)+γα(γ+α)
αβ(2-γ)+βγ(2-α)+γα(2-β)
=2∑αβ-3αβγ
=2(3)-3×4
=-6
Asked in: AP EAMCET 2020 (23 Sep Shift 1)
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