If \(\alpha, \beta, \gamma\) are the roots of \(f(x)=x^3-9 x^2+26 x\) -24, then \(\frac{1}{\alpha},…
If \(\alpha, \beta, \gamma\) are the roots of \(f(x)=x^3-9 x^2+26 x\) -24, then \(\frac{1}{\alpha}, \frac{1}{\beta}, \frac{1}{\gamma}\) are the roots of
\(24 x^3+26 x^2+9 x-1\)
\(24 x^3-26 x^2+9 x-1\)
\(24 x^3+26 x^2-9 x-1\)
\(24 x^3-26 x^2+9 x+1\)
Solution
It is given that roots of \(f(x)=x^3-9 x^2+26 x-24\) are \(\alpha, \beta, \gamma\), then the equation, where roots are \(\frac{1}{\alpha}, \frac{1}{\beta}, \frac{1}{\gamma}\). We can obtain by dividing \(f(x)\) by \(x^3\), so required equation is \(24 x^3-26 x^2+9 x-1\).
Hence, option (b) is correct.