If $\mathrm{d}_1, \mathrm{~d}_2, \mathrm{~d}_3$ are the distances of the point $(1,2,3)$ from the…

If $\mathrm{d}_1, \mathrm{~d}_2, \mathrm{~d}_3$ are the distances of the point $(1,2,3)$ from the $\mathrm{X}, \mathrm{Y}, \mathrm{Z}$-coordinate axes respectively then $2 d_2^2+d_3^2+1=$
  1. $d_1^2$
  2. $2 d_1^2$
  3. $3 d_1^2$
  4. $4 d_1^2$

Solution

We have distance $\mathrm{d}_1, \mathrm{~d}_2$ and $\mathrm{d}_3$ of the point $(1.2,3)$ from X,Y, Z. $\begin{aligned} & \Rightarrow \mathrm{d}_1=\sqrt{2^2+3^2}=\sqrt{13} \\ & \mathrm{~d}_2=\sqrt{1^2+3^2}=\sqrt{10} \\ & \mathrm{~d}_3=\sqrt{1^2+2^2}=\sqrt{5}\end{aligned}$ Now $2 \mathrm{~d}_2^2+\mathrm{d}_3^2+1=2 \times 10+5+1=26$ $=2 \mathrm{~d}_1^2$

Asked in: AP EAMCET 2022 (08 Jul Shift 1)

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