If $x_1, x_2, \ldots, x_n$ are $n$ observations such that $\sum_{i=1}^n x_1^2=400$ and $\sum_{i=1}^n x_1=80$…
If $x_1, x_2, \ldots, x_n$ are $n$ observations such that $\sum_{i=1}^n x_1^2=400$ and $\sum_{i=1}^n x_1=80$, then the least value of $n$ is
- $18$
- $12$
- $15$
- $16$
Solution
Given, $\quad \sum_{i=1}^n x_i^2=400$ and
$
\sum_{i=1}^n x_i=80
$
We know, $\frac{\Sigma\left(x_i\right)^2}{n}-\left(\frac{\Sigma x_i}{n}\right)^2 \geq 0$
$
\begin{aligned}
\Rightarrow & & \frac{400}{n}-\left(\frac{80}{n}\right)^2 & \geq 0 \\
\Rightarrow & & 400 n & \geq 6400 \\
\Rightarrow & & n & \geq 16 \\
\therefore & & n & =16
\end{aligned}
$
Asked in: AP EAMCET 2014
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