If $(1, a),(b, 2)$ are conjugate points with respect to the circle $x^2+y^2=25$, then $4 a+2 b$ is equal to

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Aicharya · Accepted Answer

Since, $(1, a)$ and $(b, 2)$ are the conjugate point of a circle, therefore point $(1, a)$ satisfy the equation (iii), we get $ \begin{aligned} b+2 a & =25 \\ \Rightarrow \quad 2 b+4 a & =50 \end{aligned} $

If $(1, a),(b, 2)$ are conjugate points with respect to the circle $x^2+y^2=25$, then $4 a+2 b$ is equal to

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