If $y=2 \sin x+3 \cos x$ and $y+A \frac{d^2 y}{d x^2}=B$, then the values of $A$, $\mathrm{B}$ are respectively

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Aicharya · Accepted Answer

$\begin{aligned} & y=2 \sin x+3 \cos x \ & 	herefore \frac{d y}{d x}=2 \cos x-3 \sin x \ & 	herefore \frac{d^2 y}{d x^2}=-2 \sin x-3 \cos x=-(2 \sin x+3 \cos x)=-y \ & 	herefore y+\frac{d^2 y}{d x^2}=0 \end{aligned}$ We have $y+A \frac{d^2 y}{d x^2}=B \Rightarrow A=1, B=0$

If $y=2 \sin x+3 \cos x$ and $y+A \frac{d^2 y}{d x^2}=B$, then the values of $A$, $\mathrm{B}$ are…

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