If $y=t^2+t^3$ and $x=t-t^4$, then the value of $\frac{d^2 y}{d x^2}$ at $t=1$ is equal to

If $y=t^2+t^3$ and $x=t-t^4$, then the value of $\frac{d^2 y}{d x^2}$ at $t=1$ is equal to
  1. $\frac{2}{3}$
  2. $\frac{-2}{3}$
  3. $\frac{4}{3}$
  4. $\frac{-4}{3}$

Solution

No solution. Refer to answer key.

Asked in: AP EAMCET 2017 (25 Apr Shift 2)

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