If $\vec{f}=\hat{i}+\hat{j}+\hat{k}$ and $\vec{g}=2 \hat{i}-\hat{j}+3 \hat{k}$ then the projection vector of…
- $\frac{2}{7}(\hat{i}+\hat{j}+\hat{k})$
- $\frac{2}{7}(2 \hat{i}-\hat{j}+3 \hat{k})$
- $\frac{1}{3}(\hat{i}+\hat{j}+\hat{k})$
- $\frac{1}{14}(2 \hat{i}-\hat{j}+3 \hat{k})$
Solution
Projection of $\vec{f}$ on $\vec{g}=\frac{\vec{f} \cdot \vec{g}}{|\vec{g}|^2} \vec{g}$ $=\frac{(2-1+3)}{(4+1+9)}(2 \hat{i}-\hat{j}+3 \hat{k})=\frac{2}{7}(2 \hat{i}-\hat{j}+3 \hat{k})$
Asked in: AP EAMCET 2024 (22 May Shift 1)