If $a>0$ and $b^2-4 a c=0$, then the curve $y=a x^2+b x+c$

If $a>0$ and $b^2-4 a c=0$, then the curve $y=a x^2+b x+c$
  1. cuts the $x$-axis
  2. touches the $x$-axis and lies below it
  3. lies entirely above the $x$-axis
  4. touches the $x$-axis and lies above it

Solution

Given, $y=a x^2+b x+c$ Since, $a>0$ and $b^2-4 a c=0$ Therefore, given curve touch the $x$-axis and lies above it.

Asked in: AP EAMCET 2011

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