If $\overrightarrow{\mathrm{L}}$ and $\overrightarrow{\mathrm{P}}$ represent the angular momentum and linear…

If $\overrightarrow{\mathrm{L}}$ and $\overrightarrow{\mathrm{P}}$ represent the angular momentum and linear momentum respectively of a particle of mass ' m ' having position vector $\overrightarrow{\mathrm{r}}=\mathrm{a}(\hat{\mathrm{i}} \cos \omega \mathrm{t}+\hat{\mathrm{j}} \sin \omega \mathrm{t})$. The direction of force is
  1. Opposite to the direction of $\vec{r}$
  2. Opposite to the direction of $\overrightarrow{\mathrm{L}}$
  3. Opposite to the direction of $\vec{P}$
  4. Opposite to the direction of $\overrightarrow{\mathrm{L}} \times \overrightarrow{\mathrm{P}}$

Solution

$\overrightarrow{\mathrm{a}}=-\omega^2 \overrightarrow{\mathrm{r}}$
$\therefore \overrightarrow{\mathrm{F}}$ opposite to $\overrightarrow{\mathrm{r}}-$

Asked in: JEE Main 2025 (04 Apr Shift 1)

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