If $\lambda$ and $K$ are de Broglie wavelength and kinetic energy, respectively, of a particle with constant mass. The correct graphical representation for the particle will be

Question

Aicharya · Accepted Answer

$\begin{aligned}
& \lambda=\frac{\mathrm{h}}{\mathrm{mv}}=\frac{\mathrm{h}}{\sqrt{2 \mathrm{mK}}} \\ & \lambda^2=\frac{\mathrm{h}^2}{2 \mathrm{~m}}\left(\frac{1}{\mathrm{k}}\right) \\ & \mathrm{Y}=\mathrm{cx}^2
\end{aligned}$
Upward facing parabola passing through origin.

If \(\lambda\) and \(K\) are de Broglie wavelength and kinetic energy, respectively, of a particle with…

Solution