If $x_1, x_2, ..., x_n$ and $\frac{1}{h_1}, $\frac{1}{h_2}$, ..., \frac{1}{h_n}$ are two A.P.s such that…

If $x_1, x_2, ..., x_n$ and $\frac{1}{h_1}, $\frac{1}{h_2}$, ..., \frac{1}{h_n}$ are two A.P.s such that $x_3 = h_2 = 8$ and $x_8 = h_7 = 20$, then $x_5 \cdot h_{10}$ is equal to
  1. 3200
  2. 1600
  3. 2650
  4. 2560

Solution

Let d1 be the common difference of the A.P. x1,x2,, then x8-x3=5 d1=12

x5=x3+2 d1=8+2×125=12.8

Let d2 be the common difference of the other sequence then

5 d2=120-18=-340d2

1 h10=1 h7+3 d2=1200h10=200

x5·h10=12.8×200=2560

Asked in: JEE Main 2018 (15 Apr)

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