If $\mathrm{g}(x)=x^2+x-1$ and (gof) $(x)=4 x^2-10 x+5$, then $\mathrm{f}(2)$ is equal to

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Aicharya · Accepted Answer

If $g(x)=x^2+x-1$ and $(g \circ f)(x)=4 x^2-10 x+5$, then $f(2)$ ? 1. Relationship: $g(f(x))=4 x^2-10 x+5$ 2. Substitute $g(x)$ : Given $g(x)=x^2+x-1$, substitute $f(x)$ : $(f(x))^2+f(x)-1=4 x^2-10 x+5$ 3. Solve for $f(x)$ : Use quadratic identities to isolate $f(x)$. Substitute $x=2$. After simplifications: Answer: -2, Option 4.

If $\mathrm{g}(x)=x^2+x-1$ and (gof) $(x)=4 x^2-10 x+5$, then $\mathrm{f}(2)$ is equal to

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