If $A=\left[\begin{array}{ccc}0 & 1+2 i & i-2 \ -1-2 i & 0 & K \ 2-1 & 7 & 0\end{array} ight]$ and $A^{-1}$ does not exists, then $K=$ (where $\mathrm{i}=\sqrt{-1}$ )

Question

If $A=\left[\begin{array}{ccc}0 & 1+2 i & i-2 \ -1-2 i & 0 & K \ 2-1 & 7 & 0\end{array}ight]$ and $A^{-1}$ does not exists, then $K=$ (where $\mathrm{i}=\sqrt{-1}$ )

Aicharya · Accepted Answer

The inverse of an order skew-symmetric does not exist Hence, $\mathrm{K}=-7$

If $A=\left[\begin{array}{ccc}0 & 1+2 i & i-2 \\ -1-2 i & 0 & K \\ 2-1 & 7 & 0\end{array}\right]$ and…

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