If $\mathrm{Q}, \mathrm{E}$ and $\mathrm{W}$ denote respectively the heat added, change in internal energy…
If $\mathrm{Q}, \mathrm{E}$ and $\mathrm{W}$ denote respectively the heat added, change in internal energy and the work done in a closed cycle process, then
$\mathrm{Q}=0$
$W=0$
$\mathrm{Q}=\mathrm{W}=0$
$\mathrm{E}=0$
Solution
From the $1^{\text {st }}$ law of thermodynamics, $\mathrm{Q}=\mathrm{E}+\mathrm{W}$
For cyclic process, $E=0, \therefore Q=W \neq 0$
~