If $x^2+y^2-6 x-8 y+12=0$ and $x^2+y^2-4 x+6 y+k=0$ cut orthogonally, then $k=$

If $x^2+y^2-6 x-8 y+12=0$ and $x^2+y^2-4 x+6 y+k=0$ cut orthogonally, then $k=$
  1. $-24$
  2. 24
  3. –48
  4. –42

Solution

No solution. Refer to answer key.

Asked in: AP EAMCET 2020 (07 Oct Special)

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