Mathematics › Vectors › Scalar Triple Product
If $\overline{\mathrm{a}}, \overline{\mathrm{b}}$ and $\overline{\mathrm{c}}$ are unit coplanar vectors,…
If $\overline{\mathrm{a}}, \overline{\mathrm{b}}$ and $\overline{\mathrm{c}}$ are unit coplanar vectors, then the scalar triple product $\left[\begin{array}{lll}2 \bar{a}-\bar{b} & 2 \bar{b}-\bar{c} & 2 \bar{c}-\bar{a}\end{array}\right]$ has the value
0 $-\sqrt{3}$ 1 $\sqrt{3}$
Solution
$\overline{\mathrm{a}}, \overline{\mathrm{b}}, \overline{\mathrm{c}}$ are coplanar vectors.
$\Rightarrow\left[\begin{array}{lll}
\overline{\mathrm{a}} & \overline{\mathrm{~b}} & \overline{\mathrm{c}}
\end{array}\right]=0$
Let $\bar{\alpha}=2 \overline{\mathrm{a}}-\overline{\mathrm{b}}, \bar{\beta}=2 \overline{\mathrm{~b}}-\overline{\mathrm{c}}$ and $\gamma=2 \overline{\mathrm{c}}-\overline{\mathrm{a}}$. Then,
$\begin{aligned}
& {\left[\begin{array}{ccc}
\bar{\alpha} & \bar{\beta} & \bar{\gamma}
\end{array}\right]=\left|\begin{array}{ccc}
2 & -1 & 0 \\
0 & 2 & -1 \\
-1 & 0 & 2
\end{array}\right|\left[\begin{array}{lll}
\overline{\mathrm{a}} & \overline{\mathrm{~b}} & \overline{\mathrm{c}}
\end{array}\right]} \\
& \Rightarrow\left[\begin{array}{lll}
\bar{\alpha} & \bar{\beta} & \bar{\gamma}
\end{array}\right]=7\left[\begin{array}{lll}
\overline{\mathrm{a}} & \overline{\mathrm{~b}} & \overline{\mathrm{c}}
\end{array}\right]=7(0)=0
\end{aligned}$
Asked in: MHT CET 2024 (16 May Shift 1)
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