If $A(2,-1)$ and $B(6,5)$ are two points the ratio in which the foot of the perpendicular from $(4,1)$ to $A…
- $8: 15$
- $5: 8$
- $-5: 8$
- $-8: 5$
Solution

$\therefore D$ divides $A B$ in the ratio $\begin{aligned} & \frac{-(2 \times 2+3 \times-1-11)}{2 \times 6+3 \times 5-11} \\ &= \frac{10}{16} \\ &= 5: 8\end{aligned}$
Asked in: AP EAMCET 2007