If $\mathrm{A} \equiv(\mathrm{x}, 4,-1), \mathrm{B} \equiv(3, \mathrm{x},-5)$ and $\mathrm{C} \equiv(2,-2…

If $\mathrm{A} \equiv(\mathrm{x}, 4,-1), \mathrm{B} \equiv(3, \mathrm{x},-5)$ and $\mathrm{C} \equiv(2,-2,3)$ are the vertices and $\mathrm{G} \equiv(2,1,-1)$ is the centroid of the triangle $A B C$, then the value of $x$ is
  1. 3
  2. 1
  3. $-2$
  4. 2

Solution

$\begin{aligned} & G \equiv\left(\frac{x+3+2}{3}, \frac{4+x-2}{3}, \frac{-1-5+3}{3}\right) \equiv(2,1,-1) \\ & \Rightarrow x=1\end{aligned}$

Asked in: MHT CET 2022 (06 Aug Shift 1)

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