If $t_1$ and $t_2$ are the times of flight of two particles having the same initial velocity $u$ and range $\mathrm{R}$ on the horizontal, then $\mathrm{t}_1^2+\mathrm{t}_2^2$ is equal to

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Aicharya · Accepted Answer

$\mathrm{t}_1=\frac{2 \mathrm{u} \sin \alpha}{\mathrm{g}}, \mathrm{t}_2=\frac{2 \mathrm{u} \sin \beta}{\mathrm{g}}$ where $\alpha+\beta=90^{\circ}$ $	herefore \mathrm{t}_1^2+\mathrm{t}_2^2=\frac{4 \mathrm{u}^2}{\mathrm{~g}^2}$

If $t_1$ and $t_2$ are the times of flight of two particles having the same initial velocity $u$ and range…

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