If $\mathrm{S}_1, \mathrm{~S}_2$ and $\mathrm{S}_3$ are the tensions at liquid-air, solid-air and…

If $\mathrm{S}_1, \mathrm{~S}_2$ and $\mathrm{S}_3$ are the tensions at liquid-air, solid-air and solid-liquid interfaces respectively, and $\theta$ is the angle of contact at the solid-liquid interface, then
  1. $\mathrm{S}_1, \cos \theta+\mathrm{S}_2 \sin \theta=\mathrm{S}_3$
  2. $S_1 \cos \theta+S_3=S_2$
  3. $S_2 \cos \theta+S_3=S_1$
  4. $S_3 \cos \theta+S_1=S_2$

Solution


At equilibrium of liquid drop, $S_2=S_1 \cos \theta+S_3$

Asked in: AP EAMCET 2024 (19 May Shift 2)

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