If $\mathrm{a}$ and $\mathrm{b}$ are the roots of the equation $\mathrm{y}^2+\mathrm{y}+1=0$, then the value…

If $\mathrm{a}$ and $\mathrm{b}$ are the roots of the equation $\mathrm{y}^2+\mathrm{y}+1=0$, then the value of $a^4+b^4+a^{-1} b^{-1}$ is
  1. $1$
  2. $0$
  3. $5$
  4. $2$

Solution

Given the equation $y^2+y+1=0$ $\begin{aligned} & \text { Now, } a^4+b^4+a^{-1} b^{-1}=a^4+b^4+\frac{1}{a b} \\ & =\left(a^2+b^2\right)^2-2 a^2 b^2+\frac{1}{1} \\ & =\left((a+b)^2-2 a b\right)^2-2 \times 1+1 \\ & =\left((-1)^2-2\right)^2-1=1-1=0 \end{aligned}$

Asked in: AP EAMCET 2023 (16 May Shift 2)

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