If α and β are the roots of the equation, 7 x 2 - 3 x - 2 = 0 , then the value of α 1 - &#945…

If  α and β are the roots of the equation, 7x2-3x-2=0, then the value ofα1-α2+β1-β2 is equal to:
  1. 2732
  2. 124
  3. 38
  4. 2716

Solution

Given α and β are the roots of the equation,7x2-3x-2=0, then 

α+β=37 ; αβ=-27

Now 

α1-α2+β1-β2=(α+β)-αβ(α+β)1-α21-β2=(α+β)-αβ(α+β)1+(αβ)2-α2+β2

(α+β)-αβ(α+β)1+(αβ)2-(α+β)2+2αβ=37+27371+272-372-227=2716

Asked in: JEE Main 2020 (05 Sep Shift 2)

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