If $\mathrm{A}(4,7,8), \mathrm{B}(2,3,4)$ and $\mathrm{C}(2,5,7)$ are the position vectors of the vertices…

If $\mathrm{A}(4,7,8), \mathrm{B}(2,3,4)$ and $\mathrm{C}(2,5,7)$ are the position vectors of the vertices of a triangle $\mathrm{ABC}$ and if the internal bisector of $\angle A$ meets $\mathrm{BC}$ at $\mathrm{D}$ then $\mathrm{AD}=$
  1. $\frac{3}{2} \sqrt{34}$
  2. $\frac{2}{3} \sqrt{34}$
  3. $\frac{1}{2} \sqrt{34}$
  4. $\frac{1}{6} \sqrt{34}$

Solution

No solution. Refer to answer key.

Asked in: AP EAMCET 2017 (24 Apr Shift 1)

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