If ' $\mathrm{n}_{\mathrm{e}}$ ' and ' $\mathrm{n}_{\mathrm{h}}$ ' are the number of electrons and number of…

If ' $\mathrm{n}_{\mathrm{e}}$ ' and ' $\mathrm{n}_{\mathrm{h}}$ ' are the number of electrons and number of holes respectively in a semiconductor heavily doped with phosphorous then
  1. $\mathrm{n}_{\mathrm{e}} \gg \mathrm{n}_{\mathrm{h}}$
  2. $\quad \mathrm{n}_{\mathrm{e}} \ll \mathrm{n}_{\mathrm{h}}$
  3. $\mathrm{n}_{\mathrm{e}} \leqslant \mathrm{n}_{\mathrm{h}}$.
  4. $\mathrm{n}_{\mathrm{e}}=\mathrm{n}_{\mathrm{h}}$

Solution

Phosphorus is a pentavalent impurity. Hence, $\mathrm{n}_{\mathrm{e}} \gg \mathrm{n}_{\mathrm{h}}$. :

Asked in: MHT CET 2024 (11 May Shift 1)

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