If $S$ and $S^{\prime}$ are the foci of the ellipse $\frac{x^2}{18}+\frac{y^2}{9}=1$ and P be a point on the…

If $S$ and $S^{\prime}$ are the foci of the ellipse $\frac{x^2}{18}+\frac{y^2}{9}=1$ and P be a point on the ellipse, then $\min \left(S P . S^{\prime} \mathrm{P}\right)+$ $\max \left(\mathrm{SP} . \mathrm{S}^{\prime} \mathrm{P}\right)$ is equal to :
  1. $3(1+\sqrt{2})$
  2. $3(6+\sqrt{2})$
  3. 9
  4. 27

Solution


$\mathrm{PS}+\mathrm{PS}^{\prime}=2 \times 3 \sqrt{2}$
$\mathrm{b}^2=\mathrm{a}^2\left(1-\mathrm{e}^2\right) \Rightarrow 9=18\left(1-\mathrm{e}^2\right)$
$\Rightarrow \mathrm{e}=\frac{1}{\sqrt{2}}$
Directrix $\mathrm{x}=\frac{\mathrm{a}}{\mathrm{e}}=\frac{3 \sqrt{2}}{\frac{1}{\sqrt{2}}}=6$
$P S \cdot P S '=\left|\frac{1}{\sqrt{2}}(3 \sqrt{2} \cos \theta-6) \frac{1}{\sqrt{2}}(3 \sqrt{2} \cos \theta+6)\right|$
$=\frac{1}{2}\left|18 \cos ^2 \theta-36\right|$
$\left(\mathrm{PS} \cdot \mathrm{PS}^{\prime}\right)_{\max }=18 ;(\mathrm{PS} \cdot \mathrm{PS})_{\min }=9$
sum $=27$

Asked in: JEE Main 2025 (02 Apr Shift 1)

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