If $x=t^2$ and $y=2 t$ are parametric equations of a curve, then equation of the normal to the curve at…
If $x=t^2$ and $y=2 t$ are parametric equations of a curve, then equation of the normal to the curve at $t=2$ is
- $2 x+y-12=0$
- $x+y-8=0$
- $x+2 y-12=0$
- $2 x+3 y-20=0$
Solution
Equation of normal at $t$
$\begin{aligned}
& (y-2 t)=\frac{-\mathrm{d} x}{\mathrm{~d} t}\left(x-t^2\right) \\
& \Rightarrow(y-2 t)=\frac{-2 t}{2}\left(x-t^2\right) \\
& \Rightarrow(y-4)=-2(x-4)[\text { for } t=2] \\
& \Rightarrow 2 x+y-12=0
\end{aligned}$
Asked in: MHT CET 2022 (08 Aug Shift 1)
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