If $b$ and $c$ are non zero real numbers, $\mathrm{A}=\left[\begin{array}{lll}1 & b & c \ b & 2 & 3 \ c & 3 & 4\end{array} ight]=\left[\begin{array}{ccc}0 & b & c \ -b & 0 & 2 \ -c & -2 & 0\end{array} ight]$ and $B$ then $\operatorname{det}(\mathrm{A}+\mathrm{B})=$

Question

If $b$ and $c$ are non zero real numbers, $\mathrm{A}=\left[\begin{array}{lll}1 & b & c \ b & 2 & 3 \ c & 3 & 4\end{array}ight]=\left[\begin{array}{ccc}0 & b & c \ -b & 0 & 2 \ -c & -2 & 0\end{array}ight]$ and $B$ then $\operatorname{det}(\mathrm{A}+\mathrm{B})=$

Aicharya · Accepted Answer

$\mathrm{A}+\mathrm{B}=\left[\begin{array}{lll}1 & b & c \ b & 2 & 3 \ c & 3 & 4\end{array}ight]+\left[\begin{array}{ccc}0 & b & c \ -b & 0 & 2 \ -c & -2 & 0\end{array}ight]$ $=\left[\begin{array}{ccc}1 & 2 b & 2 c \ 0 & 2 & 5 \ 0 & 1 & 4\end{array}ight]$ $\operatorname{det}(A+B)=\left[\begin{array}{ccc}1 & 2 b & 2 c \ 0 & 2 & 5 \ 0 & 1 & 4\end{array}ight]$ $=1(4(2)-5(1))=3$

If $b$ and $c$ are non zero real numbers, $\mathrm{A}=\left[\begin{array}{lll}1 & b & c \\ b & 2 & 3 \\ c &…

Solution