If $p$ and $q$ are distinct prime numbers and if the equation $x^2-p x+q=0$ has positive integers as its…
If $p$ and $q$ are distinct prime numbers and if the equation $x^2-p x+q=0$ has positive integers as its roots, then the roots of the equation are
- 1,-1
- 2,3
- 1,2
- 3,1
Solution
Given, $p$ and $q$ are distinct prime.
Let $p=3$ and $q=2$
$\therefore$ Given equation becomes
$
\begin{array}{rlrl}
& x^2-3 x+2 & =0 \\
\Rightarrow & x-2 x-x+2 & =0 \\
\Rightarrow & x(x-2)-1(x-2) & =0 \\
\Rightarrow & & (x-1)(x-2) & =0 \\
\Rightarrow & x & =1,2
\end{array}
$
Asked in: AP EAMCET 2014
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