If $a$ and $c$ are complex numbers and $b$ is a real number in the Argand plane, then the perpendicular…

If $a$ and $c$ are complex numbers and $b$ is a real number in the Argand plane, then the perpendicular distance from $c$ to the line $a \bar{z}+\bar{a} z+b=0$ is
  1. $\frac{(a \bar{c}+\bar{a} c+b)}{2|a|}$
  2. $\frac{(\bar{a} \bar{c}+a c+b)}{2|a|}$
  3. $\frac{(a \bar{c}+\bar{a} c+b)}{|a|}$
  4. $\frac{(\bar{a}+b+\bar{c})}{2|a|}$

Solution

No solution. Refer to answer key.

Asked in: AP EAMCET 2017 (25 Apr Shift 2)

Practice more Complex Number questions on Aicharya